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Linux Cubed Series 7: Sunsite
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continuation.scm
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1995-10-13
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; -*- Mode: Scheme; Syntax: Scheme; Package: Scheme; -*-
; Copyright (c) 1993, 1994 Richard Kelsey and Jonathan Rees. See file COPYING.
; Continuations
(define (continuation-cont c) (continuation-ref c 0))
(define (continuation-pc c) (continuation-ref c 1))
(define (continuation-template c) (continuation-ref c 2))
(define (continuation-env c) (continuation-ref c 3))
(define continuation-overhead 4)
(define (continuation-arg c i)
(continuation-ref c (+ continuation-overhead i)))
(define (continuation-arg-count c)
(- (continuation-length c) continuation-overhead))
; If (continuation-cont A) = B, then ignore B if
; 1. (continuation-template B) = (continuation-template A)
; 2. (continuation-pc B) > (continuation-pc A)
; 3. (continuation-env B) = (continuation-env A)
; or some parent of (continuation-env A)
; I don't think this is foolproof, but I have so far been unable to
; contrive a situation in which it fails. I think a double recursion of a
; procedure of no arguments is required, at the very least.
(define (continuation-parent a)
(let ((b (continuation-cont a)))
(if (and (continuation? b)
(eq? (continuation-template b) (continuation-template a))
(> (continuation-pc b) (continuation-pc a))
(let loop ((env (continuation-env a)))
(or (eq? env (continuation-env b))
(and (vector? env)
(loop (vector-ref env 0))))))
(continuation-parent b)
b)))
(define-simple-type :continuation (:value) continuation?)
(define-method &disclose ((obj :continuation))
(list 'continuation
`(pc ,(continuation-pc obj))
(template-info (continuation-template obj))))